STPM Further Maths 2009

[markwongsk]

Originally Posted by Johnivan

Hi everyone, It's a long time since i left this thread... Now i got a question for the seniors:

How do you show your complete workings for this question?

12x = 20 (mod 28 )

Thanks...

find the minimum value of x? maybe like this?

12x = 20 (mod 29 )
3x = 5 (mod 28 )
3x - 5 = 0 (mod 28 )
This implies that 3x-5 is divisible by 28 and hence
3x - 5 = mod 28n where n = 1, 2, 3...
Taking n = 1
3x - 5 = 28
x = 11

[PsyMaths]

Originally Posted by markwongsk

find the minimum value of x? maybe like this?

12x = 20 (mod 29 )
3x = 5 (mod 28 )
3x - 5 = 0 (mod 28 )
This implies that 3x-5 is divisible by 28 and hence
3x - 5 = mod 28n where n = 1, 2, 3...
Taking n = 1
3x - 5 = 28
x = 11

o this is the complete solution??? Must we take n = 1, how to know whether mayb n=101, n = 1001... has solution also???

cuz i here also got question.

Solve the following congruence:
22x = 13 (mod 44) Answer: x =1,4,7,10,13,16,19

need to try 1 by 1???

[ktan29]

Originally Posted by uoykcuf

mark has answered you in very detail way dy. lol



each book range from rm100-200
so total is rm500-1000
i got one book in my computer in pdf form, if you want u can pm me.
if u can come kedah, u can find me to ask me for the book

uoykcuf can I have the pdf form of the reference book please? Further maths is bleeding all my pocket money away .

[PsyMaths]

Originally Posted by markwongsk

find the minimum value of x? maybe like this?

12x = 20 (mod 29 )
3x = 5 (mod 28 )
3x - 5 = 0 (mod 28 )
This implies that 3x-5 is divisible by 28 and hence
3x - 5 = mod 28n where n = 1, 2, 3...
Taking n = 1
3x - 5 = 28
x = 11

Anyway, isn't that minimum value of x is 4?

12x = 20 (mod 28 )
3x = 5 (mod 7 )
3x - 5 = 0 (mod 7 )
This implies that 3x-5 is divisible by 7 and hence
3x - 5 = mod 7n where n = 1, 2, 3...
Taking n = 1
3x - 5 = 7
x = 4

[markwongsk]

Originally Posted by PsyMaths

Anyway, isn't that minimum value of x is 4?

12x = 20 (mod 28 )
3x = 5 (mod 7 )
3x - 5 = 0 (mod 7 )
This implies that 3x-5 is divisible by 7 and hence
3x - 5 = mod 7n where n = 1, 2, 3...
Taking n = 1
3x - 5 = 7
x = 4

Yeah haha I guess so... I'm not too sure about the working too. I never took FM =(

[purplesun90]

actually i want to tale fur math
but no teacher and source
so finally give up
you know....i am from lousy school...shuuu....
and there was only 1+ ppl thke fur math in whole MAY
so, anyway hope who take it, gud luck, you all genius.....muack

[ling910520]

who can give me the list of futher math refrence book that cover the entire syllabus.or if any senior here want to sell them pls pm me or email me

[Johnivan]

Originally Posted by ling910520

who can give me the list of futher math refrence book that cover the entire syllabus.

I thought I just posted something detail enough and similiar to what you want... You can check out the previous posts...

[Eurytos]

Originally Posted by purplesun90

actually i want to tale fur math
but no teacher and source
so finally give up
you know....i am from lousy school...shuuu....
and there was only 1+ ppl thke fur math in whole MAY
so, anyway hope who take it, gud luck, you all genius.....muack

Personally i feel that you shouldnt' give up so easily. There are quite alot of references out there if you really want to take further maths. Anyway your school has 10 plus people taking FM? That's a great sign!! Don't give up yet!! You can still make up for lost time if you start now!
All you need are a couple of days to find the references and kickstart your preperations for FM! Refer to earlier posts for information on Futher maths

[ling910520]

who got selling futher math reference book, new book price is not affordable leh........